document.write( "Question 918405: a particular chemical must be added to a swimming pool at regular intervals because it is released from the water into the air at the rate of 5% per hour. sixteen ounces of chemical is added at 8am. at what time will three-fourths of this chemical be gone from the pool? \n" ); document.write( "

Algebra.Com's Answer #557038 by josgarithmetic(39799) $\"\"$ $\"About$

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Assuming exponential decay,
\n" ); document.write( "c, how many ounces of chemical in the pool
\n" ); document.write( "t, amount of time after chemical addition, in hours
\n" ); document.write( "0.05 of amount lost every hour means 0.95 of amount is kept every hour.
\n" ); document.write( " $\"c=16%280.95%29%5Et\"$ ----you could also choose a somewhat different format using base e, but the one chosen here should be understandable.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The question signifies, let $\"c=%283%2F4%2916=12\"$ and solve for t. Use t to determine the time during the day when this 12 ounces is reached. \n" ); document.write( "

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