document.write( "Question 918367: David left Boston on the Coast to Coast Bike Ride, riding at 20 km/hr. Forty-five minutes later, Kristi rode out of Boston at 25 km/hr. If these speeds stay the same, how far down the road will David be when Kristi catches up to him? \n" ); document.write( "
Algebra.Com's Answer #557033 by josmiceli(19441)\"\" \"About 
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David's head start is:
\n" ); document.write( "\"+d%5B1%5D+=+20%2A%28+3%2F4+%29+\" ( 45 min = 3/4 hr )
\n" ); document.write( "\"+d%5B1%5D+=+15+\" km
\n" ); document.write( "--------------------
\n" ); document.write( "Start a stopwatch when Kristi leaves
\n" ); document.write( "Let \"+t+\" = time on the stopwatch in hrs
\n" ); document.write( "when she catches David
\n" ); document.write( "------------------------
\n" ); document.write( "Let \"+d+\" = distance in km from Boston when
\n" ); document.write( "she catches David
\n" ); document.write( "---------------------
\n" ); document.write( "David's equation:
\n" ); document.write( "(1) \"+d+-+15+=+20t+\"
\n" ); document.write( "Kristi's equation:
\n" ); document.write( "(2) \"+d+=+25t+\"
\n" ); document.write( "---------------
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+25t+-+15+=+20t+\"
\n" ); document.write( "(1) \"+5t+=+15+\"
\n" ); document.write( "(1) \"+t+=+3+\" hrs
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+=+25t+\"
\n" ); document.write( "(2) \"+d+=+25%2A3+\"
\n" ); document.write( "(2) \"+d+=+75+\" km
\n" ); document.write( "----------------
\n" ); document.write( "Kristi catches him 75 km from Boston
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+-+15+=+20t+\"
\n" ); document.write( "(1) \"+75+-+15+=+20%2A3+\"
\n" ); document.write( "(1) \"+60+=+60+\"
\n" ); document.write( "OK\r
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