document.write( "Question 77656: Solve =\r
\n" ); document.write( "\n" ); document.write( "2x2(square) + 3 = 7x
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Algebra.Com's Answer #55699 by tutorcecilia(2152)\"\" \"About 
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\"%282x%5E2+%2B+3%29\" = \"%287x%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%282x%5E2-7x+%2B+3%29\" = \"%280%29\" [Isolate all of the terms to one side and set the equation equal to zero]
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\n" ); document.write( "\n" ); document.write( "\"%282x-1%29%28x-3%29%29\" = \"%280%29\" [factor]
\n" ); document.write( "(2x-1=0 [set each factor equal to zero and solve for x]
\n" ); document.write( "2x-1=0
\n" ); document.write( "2x=1
\n" ); document.write( "x=1/2
\n" ); document.write( ".
\n" ); document.write( "(x-3)=0
\n" ); document.write( "x-3=0
\n" ); document.write( "x=3
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\n" ); document.write( "Check by plugging either value of x back into the original equation and solve.
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