document.write( "Question 918239: A man has $215,000 invested in three properties. One earns 12%, one 10% and one 8%. His annual income from the properties is $20,600 and the amount invested at 8% is twice that invested at 12%. \n" ); document.write( "
Algebra.Com's Answer #556976 by richwmiller(17219)\"\" \"About 
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total invested 215000
\n" ); document.write( "total yield 20600
\n" ); document.write( "interest rates 8,10,12
\n" ); document.write( "2 times amount at 12% invested at 8%\r
\n" ); document.write( "\n" ); document.write( "x+y+z=215000
\n" ); document.write( "0.08*x+0.1*y+0.12*z=20600
\n" ); document.write( "x=2z\r
\n" ); document.write( "\n" ); document.write( "3 equations 3 unknowns
\n" ); document.write( "x+y+z=215000,
\n" ); document.write( "2z+y+1z=215000,
\n" ); document.write( "3z+y=215000
\n" ); document.write( "y=215000-3z
\n" ); document.write( "0.08*x+0.1*y+0.12*z=20600
\n" ); document.write( "0.08*2z+0.1*y+0.12*z=20600
\n" ); document.write( "0.16*z+0.1*y+0.12*z=20600
\n" ); document.write( "0.16*z+0.12z+0.1*y=20600
\n" ); document.write( "0.28*z+0.1*y=20600
\n" ); document.write( "2.8*z+1*y=206000
\n" ); document.write( "1*y=206000-2.8*z
\n" ); document.write( "3z+y=215000
\n" ); document.write( "1*y=206000-2.8*z
\n" ); document.write( "1*y=215000-3z
\n" ); document.write( "0=-9000--0.2*z
\n" ); document.write( "-9000=-0.2*z
\n" ); document.write( "-9000/-0.2=z
\n" ); document.write( "45000=z
\n" ); document.write( "z=45000
\n" ); document.write( "1*y=215000-3z
\n" ); document.write( "1*y=215000-3*45000
\n" ); document.write( "1*y=215000-135000
\n" ); document.write( "1*y=80000
\n" ); document.write( "x+y+z=215000
\n" ); document.write( "x+80000+45000=215000
\n" ); document.write( "x=215000-y-z
\n" ); document.write( "x=90000
\n" ); document.write( "x=90000 y=80000 z=45000
\n" ); document.write( "check
\n" ); document.write( "0.08*90000+0.1*80000+0.12*45000= 20600
\n" ); document.write( "7200+8000+5400= 20600
\n" ); document.write( "ok
\n" ); document.write( "codeint3r\r
\n" ); document.write( "\n" ); document.write( "
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