document.write( "Question 917635: The length of a rectangle is 3 ft more than 5 times its width. If the perimeter is 54 ft., what are the dimensions? \n" ); document.write( "

Algebra.Com's Answer #556971 by Fombitz(32388) $\"\"$ $\"About$

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$\"L=3%2B5W\"$
\n" ); document.write( " $\"2L%2B2W=54\"$
\n" ); document.write( "Substituting,
\n" ); document.write( " $\"2%283%2B5W%29%2B2W=54\"$
\n" ); document.write( " $\"3%2B5W%2BW=27\"$
\n" ); document.write( " $\"6W=24\"$
\n" ); document.write( " $\"W=4\"$
\n" ); document.write( "Then,
\n" ); document.write( " $\"L=3%2B5%284%29\"$
\n" ); document.write( " $\"L=3%2B20\"$
\n" ); document.write( " $\"L=23\"$
\n" ); document.write( " \n" ); document.write( "

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