document.write( "Question 918193: how much water should be added to 24mL of 13% alchol solution to reduce the concentration to 12% \n" ); document.write( "
Algebra.Com's Answer #556946 by josmiceli(19441)\"\" \"About 
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Let \"+x+\" = ml of water to be added
\n" ); document.write( "\"+.13%2A24+=+3.12+\" ml of alcohol in 24% solution
\n" ); document.write( "--------------
\n" ); document.write( "\"+3.12+%2F+%28+x+%2B+24+%29+=+.12+\"
\n" ); document.write( "\"+3.12+=+.12%2A%28+x+%2B+24+%29+\"
\n" ); document.write( "\"+3.12+=+.12x+%2B+2.88+\"
\n" ); document.write( "\"+.12x+=+3.12+-+2.88+\"
\n" ); document.write( "\"+.12x+=+.24+\"
\n" ); document.write( "\"+x+=+2+\"
\n" ); document.write( "2 ml of water needs to be added
\n" ); document.write( "--------
\n" ); document.write( "check:
\n" ); document.write( "\"+3.12+%2F+%28+x+%2B+24+%29+=+.12+\"
\n" ); document.write( "\"+3.12+%2F+%28+2+%2B+24+%29+=+.12+\"
\n" ); document.write( "\"+3.12+%2F+26+=+.12+\"
\n" ); document.write( "\"+3.12+=+.12%2A26+\"
\n" ); document.write( "\"+3.12+=+3.12+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );