document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=77642>Question 77642</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In my algrebra class, we are currently solving word problems using graphing, substitution, or elimination. I have one question that I am absolutely stumped on. I cant figure out how to even begin to set the problem up. Here is the problem:  A pastry chef created a 50ounce sugar solution that was 34% sugar from a 20% sugar solution and a 40% sugar solution. How much of the 20% sugar solution and how much of the 40% sugar solution were used? Can you please help me? ~Brandi~ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55693 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> These \"mixture\" problems can sometimes be a little perplexing!<BR>\n" );
document.write( "It is helpful to think about how much sugar there is in each of the mixtures<BR>\n" );
document.write( "In the 50 ounces of 34% sugar solution you have 34% of 50 ounces of sugar.  That's 0.34(50) = 17 ounces of sugar.<BR>\n" );
document.write( "This is made up of x ounces of 20% sugar solution or 0.2x ounces of sugar, plus (50-x) ounces of 40% sugar solution or 0.4(50-x) ounces of sugar.<BR>\n" );
document.write( "Now you can make an equation to solve for x, the amount of 20% sugar solution.<BR>\n" );
document.write( "0.34(50) = 0.2x + 0.4(50-x) Simplify and solve for x.<BR>\n" );
document.write( "17 = 0.2x + 20 - 0.4x Combine like-terms.<BR>\n" );
document.write( "17 = 20-0.2x Subtract 20 from both sides.<BR>\n" );
document.write( "-3 = -0.2x  Divide both sides by -0.2<BR>\n" );
document.write( "15 = x\r<BR>\n" );
document.write( "\n" );
document.write( "So, you would need 15 ounces of 20% sugar solution plus (50-15) = 35 ounces of 40% sugar solution to obtain 50 ounces of 34% sugar solution.   </SPAN>\n" );
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