document.write( "Question 918118: Trying to work out an Algeba Equation to apply to the following, Where C=JobCost and the percentage fee reduces depending on the jobcost...\r
\n" ); document.write( "\n" ); document.write( "JobCost Fee
\n" ); document.write( "10000 35%
\n" ); document.write( "50000 30%
\n" ); document.write( "100000 25%
\n" ); document.write( "500000 20%
\n" ); document.write( "1000000 15%
\n" ); document.write( "5000000 12%
\n" ); document.write( "10000000 10%\r
\n" ); document.write( "\n" ); document.write( "I understand these may not work out exactly correct (Especially the last 2 figures!) \n" ); document.write( "
Algebra.Com's Answer #556914 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
you might want to use a curve fitting program that will fit an equation to the data.\r
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\n" ); document.write( "\n" ); document.write( "your equation looks like it will fit an exponential equation, so i'm assuming it will be something in the form of y = x^a or y = e^x.\r
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\n" ); document.write( "\n" ); document.write( "i used excel and modeled different equations to the data and the one that seems to fit the best is the power model.\r
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\n" ); document.write( "\n" ); document.write( "this models y = ax^b\r
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\n" ); document.write( "\n" ); document.write( "the equation becomes \"y+=+2.161%2Ax%5E%28-.18%29\".\r
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\n" ); document.write( "\n" ); document.write( "the R^2 value is .983 which indicates an extremely close fit.\r
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\n" ); document.write( "\n" ); document.write( "the graph is shown below:\r
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