document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=10500>Question 10500</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a+b=10.6<BR>\n" );
document.write( "a+c=8.5<BR>\n" );
document.write( "b+c=8.1<BR>\n" );
document.write( "how much are a, b, c worth?\r<BR>\n" );
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document.write( "Please help .8th grade </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5569 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5569\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can solve this sytem of equations by the substution method.\r<BR>\n" );
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document.write( "1) a + b = 10.6  or b = 10.6 - a<BR>\n" );
document.write( "2) a + c = 8.5 or c = 8.5 - a<BR>\n" );
document.write( "3) b + c = 8.1 Substitute the two above equations for b and c, then solve for a.\r<BR>\n" );
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document.write( " (10.6 - a) + (8.5 - a) = 8.1 Simplify and solve for a.<BR>\n" );
document.write( "10.6 + 8.5 - 2a = 8.1 Add 2a to both sides.<BR>\n" );
document.write( "19.1 = 8.1 + 2a  Subtract 8.1 from both sides.<BR>\n" );
document.write( "2a = 11 Divide both sides by 2<BR>\n" );
document.write( "a = 5.5\r<BR>\n" );
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document.write( "b = 10.6 - a<BR>\n" );
document.write( "b = 10.6 - 5.5<BR>\n" );
document.write( "b = 5.1\r<BR>\n" );
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document.write( "c = 8.5 - a<BR>\n" );
document.write( "c = 8.5 - 5.5<BR>\n" );
document.write( "c = 3\r<BR>\n" );
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document.write( "a = 5.5<BR>\n" );
document.write( "b = 5.1<BR>\n" );
document.write( "c = 3 </SPAN>\n" );
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