document.write( "Question 918094: the time taken by a person to cover 150km was 2.5 hrs more than the time taken in the return of the journey. if he returned at a speed of 10km per hr, more than the speed of going, what was the speed per hr in each direction in km ?/ \n" ); document.write( "
Algebra.Com's Answer #556895 by lwsshak3(11628)\"\" \"About 
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the time taken by a person to cover 150km was 2.5 hrs more than the time taken in the return of the journey. if he returned at a speed of 10km per hr, more than the speed of going, what was the speed per hr in each direction in km ?/
\n" ); document.write( "***
\n" ); document.write( "let x=speed in going direction
\n" ); document.write( "x+10=return speed
\n" ); document.write( "travel time=distance/speed
\n" ); document.write( "..
\n" ); document.write( "\"150%2Fx-150%2F%28x%2B10%29=2.5\"
\n" ); document.write( "lcd:x(x+10)
\n" ); document.write( "150(x+10)-150x=2.5x(x+10)
\n" ); document.write( "150x+1500-150x=2.5x^2+25x
\n" ); document.write( "2.5x^2+25x-1500=0
\n" ); document.write( "x^2+10-600=0
\n" ); document.write( "(x+30)(x-20)=0
\n" ); document.write( "x=20
\n" ); document.write( "x+10=30
\n" ); document.write( "speed in going direction=20 km/hr
\n" ); document.write( "return speed=30 km/hr
\n" ); document.write( " \n" ); document.write( "
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