document.write( "Question 918073: Mary collected $2.75 in nickels and dimes. Ten less than twice the number of nickels represents the number of dimes she has. How many of each kind of coin did Mary collect? \n" ); document.write( "
Algebra.Com's Answer #556879 by srinivas.g(540) You can put this solution on YOUR website! A dime is worth 2 nickels. \n" ); document.write( " let no of dimes be x \n" ); document.write( " let no of nickles be y \n" ); document.write( " so as per the data mentioned in the question , x=2*y-10 \n" ); document.write( "total amount = $2.75 \n" ); document.write( " so total amount should comprise of nickels and dimes \n" ); document.write( " x*dimes + y*nickels = $2.75 \n" ); document.write( " x*( 2 nickels)+ y *nickels = $2.75 \n" ); document.write( " => nickles( 2x+y) = $ 2.75 \n" ); document.write( " but 20 nickels = 1 dollar \n" ); document.write( " nickles(2x+y) = 2.75*20 nickels \n" ); document.write( " cancelling nickles on both sides \n" ); document.write( " 2x+y = 55 \n" ); document.write( " already we know that x= 2y-10 \n" ); document.write( " so 2(2y-10) +y= 55 \n" ); document.write( " 4y-20+y=55 \n" ); document.write( " 5y -20 =55 \n" ); document.write( " add 20 on both sides \n" ); document.write( " \n" ); document.write( " 5y-20+20=55+20 \n" ); document.write( " 5y=75 \n" ); document.write( " divide with 5 on both sides \n" ); document.write( " 5y/5 =75/5 \n" ); document.write( " y= 15 \n" ); document.write( " so x= 2y-10 \n" ); document.write( " x= 2*15-10 \n" ); document.write( " x= 30-10 \n" ); document.write( " x= 20 \n" ); document.write( "so no of dimes =20 \n" ); document.write( "no of nickels =15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |