document.write( "Question 917702: Two persons are to run a race, but one can run 12 meters per second, whereas the other can run 6 meters per second. If the slower runner has a 63-meter head start, how long will it be before the faster runner catches the slower runner, if they begin at the same time? \n" ); document.write( "
Algebra.Com's Answer #556805 by ankor@dixie-net.com(22740)\"\" \"About 
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Two persons are to run a race, but one can run 12 meters per second, whereas the other can run 6 meters per second.
\n" ); document.write( " If the slower runner has a 63-meter head start, how long will it be before the faster runner catches the slower runner, if they begin at the same time?
\n" ); document.write( ":
\n" ); document.write( "Just thinking about it, if one is running twice as fast as the other, he would cover twice the distance, in the same time or 126 ft; 126/12 = 10.5 sec
\n" ); document.write( ":
\n" ); document.write( "But here is a method, that will work for any pair of runner speeds.
\n" ); document.write( ":
\n" ); document.write( "Let d = distance ran by the slower runner
\n" ); document.write( "then
\n" ); document.write( "(d+63) = distance ran by the faster runner
\n" ); document.write( ":
\n" ); document.write( "Write a time equation time = dist/speed
\n" ); document.write( "\"d%2F6\" = \"%28%28d%2B63%29%29%2F12\"
\n" ); document.write( "cross multiply
\n" ); document.write( "12d = 6(d+63)
\n" ); document.write( "12d = 6d + 378
\n" ); document.write( "12d - 6d = 378
\n" ); document.write( "d = 378/6
\n" ); document.write( "d = 63 meters
\n" ); document.write( "find the time
\n" ); document.write( "63/6 = 10.5 sec
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