document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=917711>Question 917711</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ericas age is 8 and her mother is 42. in how many years time will the mother be 3 times older than her daughter? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #556764 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=556764\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Add some unknown number x years to both ages.  Erica will be 8+x years old.  Mom will be 42 + x.  The goal is to find x so that 3(8+x) = 42 + x - mom is three times as old.<P><BR>\n" );
document.write( "3(8+x) = 42 + x<P><BR>\n" );
document.write( "24 + 3x = 42 + x<P><BR>\n" );
document.write( "2z = 18<P><BR>\n" );
document.write( "x=9<P><BR>\n" );
document.write( "In 9 years Erica will be 17 and mom will be 51.  3 x 17 = 51 </SPAN>\n" );
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