document.write( "Question 917636: The sum of the lengths of any two sides of a triangle must be greater than the third side. If a triangle has one side that is 18 inches and a second side that is 3 inches less than twice the third side, what are the possible lengths for the second and third sides? \n" ); document.write( "
Algebra.Com's Answer #556758 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Description of the sides of your triangle:
\n" ); document.write( "18; and -3+2x; and x.\r
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\n" ); document.write( "\n" ); document.write( "According to the THEOREM you quoted, picking any two sides should conform to the theorem as stated.\r
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\n" ); document.write( "\n" ); document.write( "\"2x-3%2Bx%3E18\", picking the side #2 and side #3 to compare to side #1.
\n" ); document.write( "\"3x-3%3E18\"
\n" ); document.write( "\"3x%3E21\"
\n" ); document.write( "\"x%3E7\"
\n" ); document.write( "\"highlight%28x%3E7%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now you also need to examine comparing sum of sides 1 and 3 with length of side 2, using the triangle inequality theorem. THEN take the values for x which satisfy BOTH inequalities.\r
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\n" ); document.write( "\n" ); document.write( "\"18%2Bx%3E2x-3\"
\n" ); document.write( "\"18%2B3%3Ex\"
\n" ); document.write( "\"21%3Ex\"\r
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\n" ); document.write( "\n" ); document.write( "Do one more just to be certain.
\n" ); document.write( "\"18%2B2x-3%3Ex\"
\n" ); document.write( "\"18%2Bx-3%3E0\"
\n" ); document.write( "\"x%3E-15\", which is not very meaningful.\r
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\n" ); document.write( "\n" ); document.write( "The intersection of all three solutions is \"highlight%28x%3E21%29\".\r
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\n" ); document.write( "\n" ); document.write( "Side number 2 would be 2x-3 for x>21,
\n" ); document.write( "\"2%2A21-3\", which is 39 at its limit.
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