document.write( "Question 917638: There are 4 consecutive multiples of 3 such that the sum of the first 3 multiples is twice the fourth. Find the four multiples of 3 \n" ); document.write( "
Algebra.Com's Answer #556748 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "x = 1st multiple of 3\r\n" );
document.write( "x+3 = 2nd multiple of 3\r\n" );
document.write( "x+6 = 3rd multiple of 3\r\n" );
document.write( "x+9 = 4th multiple of 3\r\n" );
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document.write( "1st + 2nd + 3rd = 2*4th\r\n" );
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document.write( " x  + x+3 + x+6 = 2(x+9)\r\n" );
document.write( "           3x+9 = 2x+18\r\n" );
document.write( "              x = 9\r\n" );
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document.write( "x   = 1st multiple of 3 = 9\r\n" );
document.write( "x+3 = 2nd multiple of 3 =  9+3 = 12\r\n" );
document.write( "x+6 = 3rd multiple of 3 = 12+3 = 15\r\n" );
document.write( "x+9 = 4th multiple of 3 = 15+3 = 18\r\n" );
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document.write( "Edwin
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