document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=917471>Question 917471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> this is supposed to be a linear equation system problem. I couldn't find the answer. Maybe because it's a bit related to physics.\r<BR>\n" );
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document.write( "2 groups of people depart at the same time from a lodge in opposite directions. they move in a circular track. When they find each other one group has moved 38 km and the other has moved 57 km. find the average speed of each group if the second one arrived at the lodge 1 hour before the first one. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #556724 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=556724\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 groups of people depart at the same time from a lodge in opposite directions.<BR>\n" );
document.write( " they move in a circular track.<BR>\n" );
document.write( " When they find each other one group has moved 38 km and the other has moved 57 km.<BR>\n" );
document.write( " find the average speed of each group if the second one arrived at the lodge 1 hour before the first one.<BR>\n" );
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document.write( "Find the distance of the circular track: 38 + 57 = 95 km<BR>\n" );
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document.write( "The relationship of the distance each traveled is the same as the relationship of their speeds.<BR>\n" );
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document.write( "Let x = the multiplier<BR>\n" );
document.write( "then<BR>\n" );
document.write( "38x = speed of the slower group<BR>\n" );
document.write( "and<BR>\n" );
document.write( "57x = speed of the faster group<BR>\n" );
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document.write( "Write a time equation; time = dist/speed<BR>\n" );
document.write( "slow grp time - fast grp time = 1 hr<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=95%2F%2838x%29 ALIGN=MIDDLE  ALT=\"95%2F%2838x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=95%2F%2857x%29 ALIGN=MIDDLE  ALT=\"95%2F%2857x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1<BR>\n" );
document.write( "Least common multiple; 38*57 = 2166<BR>\n" );
document.write( "multiply equation by 2166x, cancel the denominators and you have<BR>\n" );
document.write( "57(95) - 38(95) = 2166x<BR>\n" );
document.write( "5415 - 3610 = 2166x<BR>\n" );
document.write( "1805 = 2166x<BR>\n" );
document.write( "x = 1505/2166<BR>\n" );
document.write( "x = .833 is the multiplier<BR>\n" );
document.write( "then<BR>\n" );
document.write( "38 * .833 = 31.67 km/hr is the speed of the slow group<BR>\n" );
document.write( "57 * .833 = 47.5 km/hr is the speed of the faster group<BR>\n" );
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document.write( "Confirm this find the time for each to make a circuit<BR>\n" );
document.write( "95/31.67 = 3.0 hrs<BR>\n" );
document.write( "95/47.50 - 2.0 hrs<BR>\n" );
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document.write( "time dif: 1 hr </SPAN>\n" );
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