document.write( "Question 917613: Graph the following conic section
\n" ); document.write( "x=y^2+6y+5
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Algebra.Com's Answer #556722 by stanbon(75887)\"\" \"About 
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Graph the following conic section
\n" ); document.write( " x=y^2+6y+5
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\n" ); document.write( "Parabola opening to the right from its vertex.
\n" ); document.write( "Vertex occurs at y = -b/(2a) = -6/(2) = -3
\n" ); document.write( "x = 9-18+5 = -4
\n" ); document.write( "Vertex(-4,-3)
\n" ); document.write( "x-intercept:: (5,0)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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