document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=917571>Question 917571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you show me how to solve e^(5ln3 - 4ln5) using the properties of logarithms? The answer is 243/625, but I want to know step by step how to get there? Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #556716 by </B><A HREF=/tutors/aboutme.mpl?userid=Hawksfan><B>Hawksfan(61)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Hawksfan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Hawksfan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=556716\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> e^(5ln3 - 4ln5)\r<BR>\n" );
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document.write( "Properties:<BR>\n" );
document.write( "1) e^(lnx) = x<BR>\n" );
document.write( "2) ln(x-y) = ln[x/y]<BR>\n" );
document.write( "3) alnb = lnb^a\r<BR>\n" );
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document.write( "by #3  e^(ln3^5 - ln5^4)\r<BR>\n" );
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document.write( "simplify  e^(ln 143 -ln625)\r<BR>\n" );
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document.write( "by rule #2 above  e^(ln143/625)\r<BR>\n" );
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document.write( "by rule #1 above  143/625 because the e cancels the ln\r<BR>\n" );
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document.write( "answer is 143/625<BR>\n" );
document.write( "e </SPAN>\n" );
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