document.write( "Question 77604: will someone help me on how to get the particular equation for the quadratic function and will you please show specific step.
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document.write( "The sluggers were up to bat in the bottom of the ninth inning in a game against
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document.write( "the ditchers. Theo Slam was up to bat. As he plugged the ball toward left
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document.write( "field, it rose from 3 to 10 to 50 feet as the horizontal distance from home
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document.write( "plate increased from 0 to 2 to 14 feet. Assume that the vertical distance
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document.write( "varies quadratically with the horizontal distance.\r
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document.write( "Can someone please help me!!!!!!!!!!!!!!''.
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Algebra.Com's Answer #55671 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Here's a way to get the equation. \n" ); document.write( ". \n" ); document.write( "Presume the equation you are looking for is of the quadratic form: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "where H = the height of the ball and x the distance the ball has traveled horizontally \n" ); document.write( "after contact with the bat. A, B, and C are constants that we will find by using the data \n" ); document.write( "that are given in the problem. \n" ); document.write( ". \n" ); document.write( "For example, we are told that at the point of contact with the bat, x is zero and the ball \n" ); document.write( "is 3 feet above the ground. Put these data into the equation we are developing and you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Notice that the terms containing A and B are both zero and therefore the equation \n" ); document.write( "reduces to 3 = C. Substitute this into the equation and the result is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Subtract 3 from both sides so that it becomes a part of the left side: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "We have two more data points. One of them is that when x = 2 ft the height of the ball \n" ); document.write( "is 10 ft. Substitute 10 for H and 2 for x to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The left side terms can be combined and the right side simplified to give: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Remember this equation. Now let's do the same thing with the final data point. That point \n" ); document.write( "is that when x = 14 ft the height of the ball is 50 ft. Substitute these two values into \n" ); document.write( "the equation to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This simplifies to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "So now we have two equations involving the two unknowns A and B. They can be solved as \n" ); document.write( "a set. These equations are: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Let's solve it by variable elimination. Let's eliminate the terms containing B. Make the \n" ); document.write( "top equation have a B term equal to the corresponding B term in the bottom equation. \n" ); document.write( "Do that by multiplying all the terms in the top equation by 7. When you do the set of \n" ); document.write( "equations becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "If you subtract the bottom equation from the top one, the B terms cancel each other and \n" ); document.write( "you are left with: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Solve for A by dividing both sides by -168 and you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "You can now solve for B by returning to an equation containing A and B as the two \n" ); document.write( "variables, and substituting \n" ); document.write( "back to our original equation of: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "We know that \n" ); document.write( "then have: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now let's take one of the data points that has an x value other than zero. It's probably \n" ); document.write( "easier to use x = 2 for a height of 10 ft. When you substitute those values you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Multiply the first term on the right side and you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Subtract 3 from both sides to eliminate the 3 on the right side. This results in: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "By dividing the numerator and denominator by 4, note that the \n" ); document.write( "to \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Add \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Putting the 7 over a denominator of 21 results in \n" ); document.write( "changes the left side to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Finally, solve for B by dividing both sides of this equation by 2 to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now putting this into the equation along with \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "That's the equation that will model the path of the ball. Let's try it to see how close \n" ); document.write( "it comes to the actual height of the ball for the three given values of x. \n" ); document.write( ". \n" ); document.write( "When x = 0, as we have seen previously, the two terms containing x go to zero and the \n" ); document.write( "equation reduces to \n" ); document.write( ". \n" ); document.write( "When x = 2, the equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "If you run this on a calculator you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "That works. As a further check let's try the point where x is 14 ft and see what height \n" ); document.write( "the ball is at at that distance. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "again, using a calculator you find that the individual terms are: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "That works also. The graph of the equation: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "models the path of the ball after the batter hits it. And the graph looks like this: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "From the graph you can see that the top part of the graph is about 254 feet up in the \n" ); document.write( "air, probably higher than a batter can hit it, and the ball goes horizontally about 286 \n" ); document.write( "feet before it hits the ground ... not likely to be far enough to be a home run unless \n" ); document.write( "you're talking Little League. \n" ); document.write( ". \n" ); document.write( "Hope this helps you understand the problem and how to develop the equation. \n" ); document.write( " |