document.write( "Question 77604: will someone help me on how to get the particular equation for the quadratic function and will you please show specific step.
\n" ); document.write( "The sluggers were up to bat in the bottom of the ninth inning in a game against
\n" ); document.write( "the ditchers. Theo Slam was up to bat. As he plugged the ball toward left
\n" ); document.write( "field, it rose from 3 to 10 to 50 feet as the horizontal distance from home
\n" ); document.write( "plate increased from 0 to 2 to 14 feet. Assume that the vertical distance
\n" ); document.write( "varies quadratically with the horizontal distance.\r
\n" ); document.write( "\n" ); document.write( "Can someone please help me!!!!!!!!!!!!!!''.
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Algebra.Com's Answer #55671 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Here's a way to get the equation.
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\n" ); document.write( "Presume the equation you are looking for is of the quadratic form:
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\n" ); document.write( "\"H+=+Ax%5E2+%2B+Bx+%2B+C\"
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\n" ); document.write( "where H = the height of the ball and x the distance the ball has traveled horizontally
\n" ); document.write( "after contact with the bat. A, B, and C are constants that we will find by using the data
\n" ); document.write( "that are given in the problem.
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\n" ); document.write( "For example, we are told that at the point of contact with the bat, x is zero and the ball
\n" ); document.write( "is 3 feet above the ground. Put these data into the equation we are developing and you get:
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\n" ); document.write( "\"3+=+A%2A%280%29%5E2+%2B+B%2A%280%29+%2B+C\"
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\n" ); document.write( "Notice that the terms containing A and B are both zero and therefore the equation
\n" ); document.write( "reduces to 3 = C. Substitute this into the equation and the result is:
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\n" ); document.write( "\"H+=+A%2Ax%5E2+%2B+B%2Ax+%2B+3\"
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\n" ); document.write( "Subtract 3 from both sides so that it becomes a part of the left side:
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\n" ); document.write( "\"H+-+3+=+A%2Ax%5E2+%2B+B%2Ax\"
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\n" ); document.write( "We have two more data points. One of them is that when x = 2 ft the height of the ball
\n" ); document.write( "is 10 ft. Substitute 10 for H and 2 for x to get:
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\n" ); document.write( "\"10++-+3+=+A%2A%282%29%5E2+%2B+B%2A%282%29\"
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\n" ); document.write( "The left side terms can be combined and the right side simplified to give:
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\n" ); document.write( "\"7+=+4%2AA+%2B+2%2AB\"
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\n" ); document.write( "Remember this equation. Now let's do the same thing with the final data point. That point
\n" ); document.write( "is that when x = 14 ft the height of the ball is 50 ft. Substitute these two values into
\n" ); document.write( "the equation to get:
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\n" ); document.write( "\"50+-+3+=+A%2A%2814%29%5E2+%2B+B%2A14\"
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\n" ); document.write( "This simplifies to:
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\n" ); document.write( "\"47+=+196%2AA+%2B+14%2AB\"
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\n" ); document.write( "So now we have two equations involving the two unknowns A and B. They can be solved as
\n" ); document.write( "a set. These equations are:
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\n" ); document.write( "\"7+=+4%2AA+%2B+2%2AB\" and
\n" ); document.write( "\"47+=+196%2AA+%2B+14%2AB\"
\n" ); document.write( ".
\n" ); document.write( "Let's solve it by variable elimination. Let's eliminate the terms containing B. Make the
\n" ); document.write( "top equation have a B term equal to the corresponding B term in the bottom equation.
\n" ); document.write( "Do that by multiplying all the terms in the top equation by 7. When you do the set of
\n" ); document.write( "equations becomes:
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\n" ); document.write( "\"49+=+28%2AA+%2B+14%2AB\" and
\n" ); document.write( "\"47+=+196%2AA+%2B+14%2AB\"
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\n" ); document.write( "If you subtract the bottom equation from the top one, the B terms cancel each other and
\n" ); document.write( "you are left with:
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\n" ); document.write( "\"2+=+-168%2AA\"
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\n" ); document.write( "Solve for A by dividing both sides by -168 and you get:
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\n" ); document.write( "\"A+=+2%2F%28-168%29+=+-1%2F84\"
\n" ); document.write( ".
\n" ); document.write( "You can now solve for B by returning to an equation containing A and B as the two
\n" ); document.write( "variables, and substituting \"-1%2F84\" for A. Just to help us, let's go all the way
\n" ); document.write( "back to our original equation of:
\n" ); document.write( ".
\n" ); document.write( "\"H+=+A%2Ax%5E2+%2B+B%2Ax+%2B+C\"
\n" ); document.write( ".
\n" ); document.write( "We know that \"A=-1%2F84\" and \"C+=+3\". Substitute those into the equation and you
\n" ); document.write( "then have:
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\n" ); document.write( "\"H+=+%28-1%2F84%29%2Ax%5E2+%2B+B%2Ax+%2B+3\"
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\n" ); document.write( "Now let's take one of the data points that has an x value other than zero. It's probably
\n" ); document.write( "easier to use x = 2 for a height of 10 ft. When you substitute those values you get:
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\n" ); document.write( "\"10+=+%28-1%2F84%29%2A2%5E2+%2B+B%2A2+%2B+3\"
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\n" ); document.write( "Multiply the first term on the right side and you get:
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\n" ); document.write( "\"10+=+-4%2F84+%2B+B%2A2+%2B+3\"
\n" ); document.write( ".
\n" ); document.write( "Subtract 3 from both sides to eliminate the 3 on the right side. This results in:
\n" ); document.write( ".
\n" ); document.write( "\"7+=+-4%2F84+%2B+B%2A2\"
\n" ); document.write( ".
\n" ); document.write( "By dividing the numerator and denominator by 4, note that the \"-4%2F84\" simplifies
\n" ); document.write( "to \"-1%2F21\". This makes the equation:
\n" ); document.write( ".
\n" ); document.write( "\"7+=+-1%2F21+%2B+B%2A2\"
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\n" ); document.write( "Add \"-1%2F21\" to both sides and you get:
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\n" ); document.write( "\"7+%2B+1%2F21+=+B%2A2\"
\n" ); document.write( ".
\n" ); document.write( "Putting the 7 over a denominator of 21 results in \"147%2F21\" and adding \"1%2F21\"
\n" ); document.write( "changes the left side to:
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\n" ); document.write( "\"148%2F21+=+2%2AB\"
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\n" ); document.write( "Finally, solve for B by dividing both sides of this equation by 2 to get:
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\n" ); document.write( "\"74%2F21+=+B\"
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\n" ); document.write( "Now putting this into the equation along with \"A+=+-1%2F84\" and \"C+=+3\" results in:
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\n" ); document.write( "\"H+=+%28-1%2F84%29%2Ax%5E2+%2B+%2874%2F21%29%2Ax+%2B+3\"
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\n" ); document.write( "That's the equation that will model the path of the ball. Let's try it to see how close
\n" ); document.write( "it comes to the actual height of the ball for the three given values of x.
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\n" ); document.write( "When x = 0, as we have seen previously, the two terms containing x go to zero and the
\n" ); document.write( "equation reduces to \"H+=+3\".
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\n" ); document.write( "When x = 2, the equation becomes:
\n" ); document.write( ".
\n" ); document.write( "\"H+=+%28-1%2F84%29%2A2%5E2+%2B+%2874%2F21%29%2A2+%2B+3\"
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\n" ); document.write( "If you run this on a calculator you get:
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\n" ); document.write( "\"H+=+-0.047619047619+%2B+7.047619047619+%2B+3+=+10\"
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\n" ); document.write( "That works. As a further check let's try the point where x is 14 ft and see what height
\n" ); document.write( "the ball is at at that distance.
\n" ); document.write( ".
\n" ); document.write( "\"H+=+%28-1%2F84%29%2A14%5E2+%2B+%2874%2F21%29%2A14+%2B+3\"
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\n" ); document.write( "again, using a calculator you find that the individual terms are:
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\n" ); document.write( "\"H+=+-2.333333333333+%2B+49.333333333333+%2B+3+=+47+%2B+3+=+50\"
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\n" ); document.write( "That works also. The graph of the equation:
\n" ); document.write( ".
\n" ); document.write( "\"H+=+%28-1%2F84%29%2Ax%5E2+%2B+%2874%2F21%29%2Ax+%2B+3\"
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\n" ); document.write( "models the path of the ball after the batter hits it. And the graph looks like this:
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\n" ); document.write( "From the graph you can see that the top part of the graph is about 254 feet up in the
\n" ); document.write( "air, probably higher than a batter can hit it, and the ball goes horizontally about 286
\n" ); document.write( "feet before it hits the ground ... not likely to be far enough to be a home run unless
\n" ); document.write( "you're talking Little League.
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\n" ); document.write( "Hope this helps you understand the problem and how to develop the equation.
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