document.write( "Question 77607: Hi there, I was wondering if someone can help me solve this rectangle problem?\r
\n" ); document.write( "\n" ); document.write( "It says:\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle decreased by 6cm is equal to the width. If the perimeter is 68 cm, find its dimensions.\r
\n" ); document.write( "\n" ); document.write( "It would be greatly appreciated!!!!\r
\n" ); document.write( "\n" ); document.write( "Thank you.
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Algebra.Com's Answer #55668 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If we let L=length, w=width we get\r
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\n" ); document.write( "\n" ); document.write( "\"L-6=w\" and the perimeter equals \r
\n" ); document.write( "\n" ); document.write( "\"P=2L%2B2w\"\r
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\n" ); document.write( "\n" ); document.write( "\"68=2L%2B2%28L-6%29\" Plug in L-6 into w and let P=68\r
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\n" ); document.write( "\n" ); document.write( "\"68=2L%2B2L-12\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"68=4L-12\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"80=4L\" Add 12 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"80%2F4=L\" Divide both sides by 4\r
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\n" ); document.write( "\n" ); document.write( "\"L=20\" So this is the length\r
\n" ); document.write( "\n" ); document.write( "Use this to find the width:\r
\n" ); document.write( "\n" ); document.write( "\"20-6=w\"\r
\n" ); document.write( "\n" ); document.write( "\"w=14\"\r
\n" ); document.write( "\n" ); document.write( "So the dimensions are width=14, length=20\r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "\"68=2%2820%29%2B2%2814%29\" plug in L=20, w=14, P=68\r
\n" ); document.write( "\n" ); document.write( "\"68=40%2B28\"\r
\n" ); document.write( "\n" ); document.write( "\"68=68\" works
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