document.write( "Question 917467: I'm having trouble with this question: \"Given the length of a rectangle is one less than four times the width. The perimeter of the rectangle is 88. Find the dimensions of the rectangle.\" So I put it into an equation of 4x-1=88. I worked out the equation, but then I was left with 89/4. It became a decimal of 22.25, but I have to find the dimensions of the rectangle which would be finding the length and width I suppose which is not the same size. Can someone please help me of solving this problem? \n" ); document.write( "
Algebra.Com's Answer #556676 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! let x be the width of the rectangle, then \n" ); document.write( "length = 4x -1 \n" ); document.write( "Perimeter(P) = 2l + 2w \n" ); document.write( "P = 2(4x-1) + 2x \n" ); document.write( "now the perimeter is 88, therefore \n" ); document.write( "88 = 8x-2 +2x \n" ); document.write( "10x = 90 \n" ); document.write( "x = 9 \n" ); document.write( "therefore \n" ); document.write( "width = 9 and length = 35 \n" ); document.write( " \n" ); document.write( " |