document.write( "Question 917415: The equation of the parabola whose focus is at (0, 5) and directrix at y = -5 is \n" ); document.write( "
Algebra.Com's Answer #556654 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the focus is at (0,5) \n" ); document.write( "the directrix is at y = -5 \n" ); document.write( "the vertex is halftway between the focus and the intersection of the directrix with the axis of symmetry. \n" ); document.write( "that would make the vertex at (0,0).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the vertex form of the equation of a parabola is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = a * (x-h)^2 + k\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the conic form of the equation of a parabola is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4p * (y-k) = (x-h)^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p is the distance from the directrix to the vertex and from the vertex to the focus.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that makes p half the distance between the focus and the directrix on the axis of symmetry.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that makes p = 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "from the conic form of the equation of a parabola, you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4p * (y-k) = (x-h)^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since the vertex is at (0,0), this equation becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4p * y = x^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since p = 5, this equation becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20 * y = x^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of this equation by 20 and you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = (1/20) * x^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's your equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in the vertex form of your equation, you have:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = a(x-h)^2 + k\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since h = 0 and k = 0 and a = 1/(4p) and p = 5, you then get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = (1/20) * x^2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the vertex form of the equation and the conic form of the equation can be directly translated into each other with a = 1/(4p) or 4p = 1/a.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the graph of your equation is shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |