document.write( "Question 917250: find four consecutive odd integers whose sum is 496 \n" ); document.write( "
Algebra.Com's Answer #556609 by Edwin McCravy(20081)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "First way is without algebra.\r\n" );
document.write( "Second way is using algebra.\r\n" );
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document.write( "First way:\r\n" );
document.write( "They'll have to average 1/4th of 496 which is 124.\r\n" );
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document.write( "So get the two odd numbers just below 124 and the two odd numbers\r\n" );
document.write( "just above 124 and you have them:\r\n" );
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document.write( "121 + 123 + 125 + 127 = 496.\r\n" );
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document.write( "But your teacher won't allow that method because it doesn't use \r\n" );
document.write( "algebra.\r\n" );
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document.write( "Using algebra\r\n" );
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document.write( "first odd integer = n\r\n" );
document.write( "second odd integer = n+2\r\n" );
document.write( "third odd integer = n+4\r\n" );
document.write( "fourth odd integer = n+6\r\n" );
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document.write( "n + n+2 + n+4 + n+6 = 496\r\n" );
document.write( "              4n+12 = 496\r\n" );
document.write( "                 4n = 484\r\n" );
document.write( "                  n = 121\r\n" );
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document.write( "So they are  \r\n" );
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document.write( "first odd integer = n = 121\r\n" );
document.write( "second odd integer = n+2 = 121+2 = 123\r\n" );
document.write( "third odd integer = n+4 = 121+4 = 125\r\n" );
document.write( "fourth odd integer = n+6 = 121+6 = 127\r\n" );
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document.write( "Edwin
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