document.write( "Question 917283: Find the equation of the circle that passes through (8,3) and (2,3) and has its centre on the x-axis.\r
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Algebra.Com's Answer #556600 by josgarithmetic(39620)\"\" \"About 
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The center on the x-axis and those two given points form an isosceles triangle, and the x-coordinate of the center of the circle should be in the middle of x=8 and x=3.\r
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\n" ); document.write( "\n" ); document.write( "That center has y=0, because the point is given as ON THE x-AXIS. \r
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\n" ); document.write( "\n" ); document.write( "Center is the point (5,0).\r
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\n" ); document.write( "\n" ); document.write( "Use either of the given points and Distance Formula to calculate and then compute the radius of the circle. \r
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\n" ); document.write( "\n" ); document.write( "Now just fill-in the necessary values for the standard form equation of a circle.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28%288-5%29%5E2%2B%283-0%29%5E2%29\"
\n" ); document.write( "\"sqrt%28%283%29%5E2%2B%283%29%5E2%29\"
\n" ); document.write( "\"sqrt%2818%29\"\r
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\n" ); document.write( "\n" ); document.write( "When you square that, you have 18, which is \"r%5E2\" for the standard form equation.\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28%28x-5%29%5E2%2By%5E2=18%29\"
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