document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=10452>Question 10452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would i work out 5x-1=6-3x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5566 by </B><A HREF=/tutors/aboutme.mpl?userid=askmemath><B>askmemath(368)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=askmemath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5566\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x-1=6-3x\r<BR>\n" );
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document.write( "Bring all the terms containing x to 1 side and put the remaining terms on the other side.<BR>\n" );
document.write( "However,when variable move from side to another, the sign changes \r<BR>\n" );
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document.write( "SO <BR>\n" );
document.write( "5x+3x = 6+1 (Subtraction on 1 side becomes addition on the other)<BR>\n" );
document.write( "8x = 7\r<BR>\n" );
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document.write( "x = 7/8    </SPAN>\n" );
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