document.write( "Question 917285: How do I find ln sixth root of e without a calculator? My options for answers is 1/e , 6, 1/6, or e. Thank you so much for explaining how to execute this. I'm not sure if we can cancel the ln and e if the e is under the square root. \n" ); document.write( "
Algebra.Com's Answer #556597 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
\"e%5E%281%2F6%29\"\r
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\n" ); document.write( "\n" ); document.write( "No Calculator? Table of Natural logarithms!\r
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\n" ); document.write( "\n" ); document.write( "\"e%5E%281%2F6%29=N\"
\n" ); document.write( "\"ln%28e%5E%281%2F6%29%29=ln%28N%29\"
\n" ); document.write( "\"%281%2F6%29%2A1=ln%28N%29\"
\n" ); document.write( "Use the table to find or determine natural log of \"1%2F6\".\r
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\n" ); document.write( "\n" ); document.write( "(1.181, but I used a calculator.)\r
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\n" ); document.write( "\n" ); document.write( "Here is an online table:
\n" ); document.write( "http://myhandbook.info/table_naperlog.html\r
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\n" ); document.write( "\n" ); document.write( "The mantissa nearest to \"1%2F6\" is 0.165514.
\n" ); document.write( "This is for log of 1.800.
\n" ); document.write( "What you want is between 1.8 and 1.9;
\n" ); document.write( "Use linear interpolation to get a more accurate value.\r
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\n" ); document.write( "\n" ); document.write( "N_______________Natural Logarithm
\n" ); document.write( "1.800___________0.165514
\n" ); document.write( "v_______________0.16666666666...
\n" ); document.write( "1.900___________0.173953\r
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\n" ); document.write( "\n" ); document.write( "The choices which you say from which you must choose are all equally bad.
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