document.write( "Question 917221: How do I figure out the graph for: f(x) = 3(2^x)-6\r
\n" ); document.write( "\n" ); document.write( "I know that x=-6 is the horizontal asymptote\r
\n" ); document.write( "\n" ); document.write( "when I go to make a t-table my points are all over the place and not consistent.\r
\n" ); document.write( "\n" ); document.write( "like plugging in x=1 results in 0. x=2 results in 6...\r
\n" ); document.write( "\n" ); document.write( "What is the proper way to figure out this graph?
\n" ); document.write( "Thank you
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Algebra.Com's Answer #556586 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
The factor 3, just stretches the graph vertically. The minus 6 moves the graph downward by 6 units. \r
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\n" ); document.write( "\n" ); document.write( "Work with easy values to help get good points to sketch the graph.\r
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\n" ); document.write( "\n" ); document.write( "x____________f(x)
\n" ); document.write( "-2_________\"3%282%5E%28-2%29%29-6=3%2F4-6=-5%261%2F4\"
\n" ); document.write( "-1_________\"3%282%5E%28-1%29%29-6=3%2F2-6=-4%261%2F2\"
\n" ); document.write( "0__________\"3%282%5E0%29-6=3\"
\n" ); document.write( "1__________\"3%2A2-6=0\"
\n" ); document.write( "2__________\"3%2A2%5E2-6=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C3%2A2%5Ex-6%29\"\r
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\n" ); document.write( "\n" ); document.write( "For comparison this is 2^x:
\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C2%5Ex%29\"
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