document.write( "Question 917230: R(t) = 8 - (3)/(2x+4)\r
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document.write( "Please explain how I would go about finding the graph for this. Please give as many details as possible.\r
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document.write( "I know that the vertical asymptote is x=-2, and I guess there is no horizontal asymptote because there is no x's in the numerator.\r
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document.write( "How would I start finding points on the x-axis and overall figuring this out?\r
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document.write( "Thanks! \n" );
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Algebra.Com's Answer #556575 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! as x gets really really big, and heads off to infinity, 2x+4 blows up to infinity.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we have 3/(infinity) more or less as x approaches infinity.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The whole fraction - (3)/(2x+4) approaches 0 as x ---> infinity.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So as x ---> infinity, 8 - (3)/(2x+4) turns into 8 - 0 more or less. That turns into 8.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the horizontal asymptote is y = 8.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This same logic applies to negative infinity as well.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let me know if you need more help or if you need me to explain a step in more detail. \n" ); document.write( "Feel free to email me at jim_thompson5910@hotmail.com \n" ); document.write( "or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thanks,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jim \n" ); document.write( " |