document.write( "Question 917170: I am stuck on this problem and need help. \r
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document.write( "You have 53 coins consisting of dimes and pennies. The number of pennies is 7 less than twice the number of dimes. \r
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document.write( "1.) How many pennies do you have?
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document.write( "2.) How many dimes do you have? \n" );
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Algebra.Com's Answer #556552 by ewatrrr(24785) You can put this solution on YOUR website! x the number of dimes \n" ); document.write( "53 coins \n" ); document.write( "# ofdimes + # of pennies = 53 \n" ); document.write( "x + (2x-7) = 53 \n" ); document.write( "3x = 60 \n" ); document.write( "x = 20, the number of dimes and 33 pennies \n" ); document.write( "and...checking \n" ); document.write( "20 + 33 = 53 coins \n" ); document.write( " \n" ); document.write( " |