document.write( "Question 917170: I am stuck on this problem and need help. \r
\n" ); document.write( "\n" ); document.write( "You have 53 coins consisting of dimes and pennies. The number of pennies is 7 less than twice the number of dimes. \r
\n" ); document.write( "\n" ); document.write( "1.) How many pennies do you have?
\n" ); document.write( "2.) How many dimes do you have?
\n" ); document.write( "

Algebra.Com's Answer #556552 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
x the number of dimes
\n" ); document.write( "53 coins
\n" ); document.write( "# ofdimes + # of pennies = 53
\n" ); document.write( "x + (2x-7) = 53
\n" ); document.write( "3x = 60
\n" ); document.write( "x = 20, the number of dimes and 33 pennies \"2%2A20-7\"
\n" ); document.write( "and...checking
\n" ); document.write( "20 + 33 = 53 coins
\n" ); document.write( "
\n" ); document.write( "
\n" );