document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=917046>Question 917046</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi I would like to receive help solving for \"Y\" in terms of \"X\" for the problem below.\r<BR>\n" );
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document.write( "3X-5Y=25 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #556481 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=556481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3X-5Y=25<BR>\n" );
document.write( "subtract 3x from both sides of =<BR>\n" );
document.write( "-5y = 25 - 3x<BR>\n" );
document.write( "divide both sides of = by -5<BR>\n" );
document.write( "y = -5 + 3x/5\r<BR>\n" );
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document.write( " </SPAN>\n" );
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