document.write( "Question 916979: T he sum of the ages of two boys is 50 . In 5 years time the elder brother will be four times the younger brother . Find their ages \n" ); document.write( "

Algebra.Com's Answer #556449 by mananth(16946) $\"\"$ $\"About$

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\n" ); document.write( "x+y=50\r
\n" ); document.write( "\n" ); document.write( "After 5 years\r
\n" ); document.write( "\n" ); document.write( "ages
\n" ); document.write( "x+5
\n" ); document.write( "y+5\r
\n" ); document.write( "\n" ); document.write( "y+5=2(x+5)
\n" ); document.write( "y+5=2x+10
\n" ); document.write( "y-2x=5\r
\n" ); document.write( "\n" ); document.write( "x= one boy's age
\n" ); document.write( "y= second boy's age
\n" ); document.write( "
\n" ); document.write( "1 x + 1 y = 50 .............1
\n" ); document.write( "
\n" ); document.write( "-2 x + 1 y = 5 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -1
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-1 x -1 y = -50
\n" ); document.write( "-2 x + 1 y = 5
\n" ); document.write( "Add the two equations
\n" ); document.write( "-3 x = -45
\n" ); document.write( "/ -3
\n" ); document.write( "x = 15
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "1 x + 1 y = 50
\n" ); document.write( "15 + y = 50
\n" ); document.write( " y = 50
\n" ); document.write( " y = 35
\n" ); document.write( " y = 35
\n" ); document.write( "x= 15 one boy's age
\n" ); document.write( "y= 35 second boy's age
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "

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