document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=916935>Question 916935</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars start from towns 400 miles apart and travel toward each other. They meet after 4 hrs. Find the rate of each car if one travels 20 mph faster than the other. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #556446 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=556446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two cars start from towns 400 miles apart and travel toward each other. They meet after 4 hrs. Find the rate of each car if one travels 20 mph faster than \r<BR>\n" );
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document.write( "Two cars start from towns 400 miles apart=d\r<BR>\n" );
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document.write( "let speed of one be x mph<BR>\n" );
document.write( "other will be x+20 mph\r<BR>\n" );
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document.write( " and travel toward each other. add up speeds<BR>\n" );
document.write( "x+x+20<BR>\n" );
document.write( "=2x+20\r<BR>\n" );
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document.write( " They meet after 4 hrs.=t\r<BR>\n" );
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document.write( "t=d/r\r<BR>\n" );
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document.write( "t= 400/(2x+20) =4\r<BR>\n" );
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document.write( "400=8x+80\r<BR>\n" );
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document.write( "8x=320\r<BR>\n" );
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document.write( "x=40 mph\r<BR>\n" );
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document.write( "40 & 60 mph  </SPAN>\n" );
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