document.write( "Question 916873: Abby rows 10km upstream and 10km back in a total time of 3hrs. The speed of the river is 5km/h. Find abby's speed in still water. \n" ); document.write( "
Algebra.Com's Answer #556444 by mananth(16946)![]() ![]() You can put this solution on YOUR website! boat speed x mph Time forward + time return = hours \n" ); document.write( "current speed 5 mph \n" ); document.write( " \n" ); document.write( "against current x- 5 km/h \n" ); document.write( "with current x+ 5 km/h \n" ); document.write( " \n" ); document.write( "Distance= 10 miles \n" ); document.write( " \n" ); document.write( "Time against + time with = 3 hours \n" ); document.write( "t=d/r \n" ); document.write( " \n" ); document.write( "10 /( x + 5 ) + 10 /(x - 5 ) = 3 \n" ); document.write( " \n" ); document.write( "LCD = (x - 5 ) ( x + 5 ) \n" ); document.write( "10 *( x - 5 ) + 10 (x + 5 ) = 3 (x^2 - 25 ) \n" ); document.write( "10 x - -50 + 10 x + 50 = 3 ( x ^2 - 25 ) \n" ); document.write( "20 x = 3 x ^2 -75 \n" ); document.write( "3 x ^2 - -20 x - -75 = 0 \n" ); document.write( " \n" ); document.write( "Find the roots of the equation by quadratic formula 5.12 \n" ); document.write( " \n" ); document.write( "a= 3 , b= -20 , c= -75 \n" ); document.write( " \n" ); document.write( "b^2-4ac= 400 + 900 \n" ); document.write( "b^2-4ac= 1300 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x1=( 20 + 36.06 )/ 6 \n" ); document.write( "x1= 9.34 \n" ); document.write( " \n" ); document.write( "x2=( 20 -36.06 ) / 6 \n" ); document.write( "x2= -2.68 \n" ); document.write( "Ignore negative value \n" ); document.write( "boat speed 9.343 km/h \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |