document.write( "Question 916974: in the morning May drove to an appointment at 50 mph. her average speed on the return trip in the afternoon was 40 mph. the return trip took 1/2 hour longer . how far did she travel to the appointment \n" ); document.write( "
Algebra.Com's Answer #556442 by mananth(16946)![]() ![]() You can put this solution on YOUR website! distance = x \n" ); document.write( "Time to go there x/ 50 \n" ); document.write( "return time x/ 40 \n" ); document.write( "exrta time = 0.50 hour \n" ); document.write( "x/ 40 - x/ 50 = 0.50 \n" ); document.write( " \n" ); document.write( "LCD = 7350 2000 \n" ); document.write( "multiply by LCD = \n" ); document.write( "50 - 40 x 0.50 * 2000 \n" ); document.write( "10 x= 1000 \n" ); document.write( "/ 10 \n" ); document.write( "x= 100 miles \n" ); document.write( " \n" ); document.write( " |