document.write( "Question 916964: The product of two numbers is 44. One number is 3 more than twice the other number. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #556435 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let one number be x \n" ); document.write( "other number = 2x+3\r \n" ); document.write( "\n" ); document.write( "x(2x+3)=44\r \n" ); document.write( "\n" ); document.write( "2x^2+3x=44\r \n" ); document.write( "\n" ); document.write( "2x^2+3x-44=0\r \n" ); document.write( "\n" ); document.write( "2x^2+11x-8x-44=0\r \n" ); document.write( "\n" ); document.write( "x(2x+11)-4(2x+11)=0\r \n" ); document.write( "\n" ); document.write( "(2x+11)(x-4)=0\r \n" ); document.write( "\n" ); document.write( "x=4 \n" ); document.write( "other number = 2x+3 => 2*4+3=11\r \n" ); document.write( "\n" ); document.write( "the numbers are 4 & 11\r \n" ); document.write( "\n" ); document.write( "x=-5.5\r \n" ); document.write( "\n" ); document.write( " other number =-11+3=-8\r \n" ); document.write( "\n" ); document.write( "-5.5 & -8\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |