document.write( "Question 916964: The product of two numbers is 44. One number is 3 more than twice the other number. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #556435 by mananth(16946)\"\" \"About 
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let one number be x
\n" ); document.write( "other number = 2x+3\r
\n" ); document.write( "\n" ); document.write( "x(2x+3)=44\r
\n" ); document.write( "\n" ); document.write( "2x^2+3x=44\r
\n" ); document.write( "\n" ); document.write( "2x^2+3x-44=0\r
\n" ); document.write( "\n" ); document.write( "2x^2+11x-8x-44=0\r
\n" ); document.write( "\n" ); document.write( "x(2x+11)-4(2x+11)=0\r
\n" ); document.write( "\n" ); document.write( "(2x+11)(x-4)=0\r
\n" ); document.write( "\n" ); document.write( "x=4
\n" ); document.write( "other number = 2x+3 => 2*4+3=11\r
\n" ); document.write( "\n" ); document.write( "the numbers are 4 & 11\r
\n" ); document.write( "\n" ); document.write( "x=-5.5\r
\n" ); document.write( "\n" ); document.write( " other number =-11+3=-8\r
\n" ); document.write( "\n" ); document.write( "-5.5 & -8\r
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