document.write( "Question 916968: write the equation of the line that passes through (2 5) and perpendicular to the line 2y-3x=5. Write the answer in standard form. \n" ); document.write( "
Algebra.Com's Answer #556432 by mananth(16946)\"\" \"About 
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-3 x + 2 y = 5
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "2 y = 3 x + 5
\n" ); document.write( "Divide by 2
\n" ); document.write( " y = 1 1/ 2 x + 2 1/2
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = 1 1/2
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal - 2/3
\n" ); document.write( "Because m1*m2 =-1
\n" ); document.write( "The slope of the required line will be - 2/3
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\n" ); document.write( "m= - 2/3 ,point ( 2 , 5 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "5 = -1 1/ 3 + b
\n" ); document.write( "b= 6 1/3
\n" ); document.write( "m= - 2/3
\n" ); document.write( "The required equation is y = - 2/ 3 x + 19/ 3 \r
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\n" ); document.write( "\n" ); document.write( "3y=-2x+19\r
\n" ); document.write( "\n" ); document.write( "2x+3y=19
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\n" ); document.write( "m.ananth@hotmail.ca
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