document.write( "Question 916953: a man invested 100000. he put part 5% interest. on the other hand, he invested the remainder in bonds with 9% yearly return. How much did he put in the banks if his yearly income from the two investments was 7400? \n" ); document.write( "
Algebra.Com's Answer #556421 by mananth(16949)\"\" \"About 
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Part I 5.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 9.00% per annum ------------ Amount invested = y
\n" ); document.write( " 100000
\n" ); document.write( "Interest----- 7400.00
\n" ); document.write( "
\n" ); document.write( "Part I 5.00% per annum ---x
\n" ); document.write( "Part II 9.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 100000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "5.00% x + 9.00% y= 7400
\n" ); document.write( "Multiply by 100
\n" ); document.write( "5 x + 9 y= 740000.00 --------2
\n" ); document.write( "Multiply (1) by -5
\n" ); document.write( "we get
\n" ); document.write( "-5 x -5 y= -500000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 4 y= 240000
\n" ); document.write( "divide by 4
\n" ); document.write( " y = 60000
\n" ); document.write( "Part I 5.00% $ 40000
\n" ); document.write( "Part II 9.00% $ 60000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "40000 --------- 5.00% ------- 2000.00
\n" ); document.write( "60000 ------------- 9.00% ------- 5400.00
\n" ); document.write( "Total -------------------- 7400.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
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