document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=916957>Question 916957</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me solve this problem. A container holds 3 liters of a 25 % alcohol solution. One half liter of the solution is withdrawn and replaced with one half liter of pure alcohol. What is the percentage of alcohol in new mixture ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #556420 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=556420\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are adding 1.5 liters of 100% alcohol to 25% solution to get 3 liters of mixture.\r<BR>\n" );
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document.write( "Let the percentage of mixture be x\r<BR>\n" );
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document.write( "1.5*100% + 1.5*25% = 3*x%\r<BR>\n" );
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document.write( "multiply by 100\r<BR>\n" );
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document.write( "1.5+37.5=3x<BR>\n" );
document.write( "39=3x<BR>\n" );
document.write( "x=13 %\r<BR>\n" );
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document.write( " </SPAN>\n" );
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