document.write( "Question 916868: Confused about this logarithm\r
\n" ); document.write( "\n" ); document.write( "Suppose log a = 0.3, log b = -0.5. Evaluate\r
\n" ); document.write( "\n" ); document.write( "log(1000 a²)
\n" ); document.write( "= log(1000) + log(a²)
\n" ); document.write( "= 3 + 2 log(a)
\n" ); document.write( "= 3 + 2*0.3
\n" ); document.write( "= 3.6 \r
\n" ); document.write( "\n" ); document.write( "I understand everything up until 3+2log(a) after that why does the 2 log(a) become only 0.3? since 1000 becomes 3 due to log(base 10) 1000 = 3. Wouldn't the same be true for 2log(a) being something like 2log(base 10)(0.3) and then getting a different answer other than 0.3?\r
\n" ); document.write( "\n" ); document.write( "Please help thanks! \n" ); document.write( "

Algebra.Com's Answer #556339 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
Suppose log a = 0.3, log b = -0.5. Evaluate
\n" ); document.write( "log(1000 a²)
\n" ); document.write( "= log(1000) + log(a²)
\n" ); document.write( "= 3 + 2 log(a)
\n" ); document.write( "-------
\n" ); document.write( "2*log(a) = 2*0.3 = 0.6
\n" ); document.write( "-------------------------------
\n" ); document.write( "= 3 + 2*0.3
\n" ); document.write( "= 3 + 0.6
\n" ); document.write( "------
\n" ); document.write( "= 3.6
\n" ); document.write( "==============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "-----------------
\n" ); document.write( " \n" ); document.write( "

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