document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=916868>Question 916868</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Confused about this logarithm\r<BR>\n" );
document.write( "\n" );
document.write( "Suppose log a = 0.3, log b = -0.5. Evaluate\r<BR>\n" );
document.write( "\n" );
document.write( "log(1000 aČ) <BR>\n" );
document.write( "= log(1000) + log(aČ) <BR>\n" );
document.write( "= 3 + 2 log(a) <BR>\n" );
document.write( "= 3 + 2*0.3 <BR>\n" );
document.write( "= 3.6 \r<BR>\n" );
document.write( "\n" );
document.write( "I understand everything up until 3+2log(a) after that why does the 2 log(a) become only 0.3? since 1000 becomes 3 due to log(base 10) 1000 = 3. Wouldn't the same be true for 2log(a) being something like 2log(base 10)(0.3) and then getting a different answer other than 0.3?\r<BR>\n" );
document.write( "\n" );
document.write( "Please help thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #556338 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=556338\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose log a = 0.3, log b = -0.5. Evaluate\r<BR>\n" );
document.write( "\n" );
document.write( "log(1000 aČ) <BR>\n" );
document.write( "= log(1000) + log(aČ) <BR>\n" );
document.write( "= 3 + 2 log(a) <BR>\n" );
document.write( "= 3 + 2*0.3 <BR>\n" );
document.write( "= 3.6 \r<BR>\n" );
document.write( "\n" );
document.write( "I understand everything up until 3+2log(a) after that why does the 2 log(a) become only 0.3? ****************<BR>\n" );
document.write( "It doesn't, it's 2 times 0.3<BR>\n" );
document.write( "===========================<BR>\n" );
document.write( "since 1000 becomes 3*********** 1000 doesn't become 3.  Log(1000) = 3 ********* due to log(base 10) 1000 = 3. Wouldn't the same be true for 2log(a) being something like 2log(base 10)(0.3) and then getting a different answer other than 0.3?<BR>\n" );
document.write( "It's 2 times, = 0.6.  You entered it yourself.<BR>\n" );
document.write( "Your answer is correct. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );