document.write( "Question 916833: Figuring out graphing of this polynomial:\r
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document.write( "f(x) = 12x^3 - 12x^2 - 24x\r
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document.write( "what I have so far:
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document.write( "I know I can factor it down, therefore 12x(x+1)(x-2)
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document.write( "and the x-int would be (-1,0),(2,0)
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document.write( "But why is (0,0) also a factor? I don't understand that.\r
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document.write( "also how would I find the degree and leading coefficient? very lost on that concept\r
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document.write( "And when I plug this poly into a graphing calculator it has a steepness and a lowness at two points. I am in precalculus so I don't know the finer details of graphing/derivatives and I must be able to do this freehand how would I know how far up to make the graph and how far low to make the graph?\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #556318 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! But WHY is (0,0) also a factor?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I just answered this question a few minutes ago.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "LOOK at the factorization of f(x). You have the correct factorization. Three separate factors written in x. \n" ); document.write( "The list of factors: \n" ); document.write( "x \n" ); document.write( "(x+1) \n" ); document.write( "(x-2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Each of those gives a x-intercept. \n" ); document.write( "Note that one of the factors is x, so this means that when x=0, f is also zero, BECAUSE x IS ONE OF THE FACTORS OF THE FUNCTION f. \n" ); document.write( " |