document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=77517>Question 77517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 4 less than twice its width. if the area of the rectangle is 20, find the width of the rectangle to the nearest tenth </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55631 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55631\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2W-4 IS THE LENGTH WHILE W=WIDTH<BR>\n" );
document.write( "AREA=W*L<BR>\n" );
document.write( "20=W(2W-4)<BR>\n" );
document.write( "20=2W^2-4W<BR>\n" );
document.write( "2W^2-4W-20=0<BR>\n" );
document.write( "USING THE QUADRATIC EQUATION WE GET<BR>\n" );
document.write( "W=(4+-SQRT[-4^2-4*2*-20])/2*2<BR>\n" );
document.write( "W=(4+-SQRT[16+160])/4<BR>\n" );
document.write( "W=(4+-SQRT176)/4<BR>\n" );
document.write( "W=(4+-13.2665)/4<BR>\n" );
document.write( "W=(4+13.2665)/4<BR>\n" );
document.write( "W=17.2665/4<BR>\n" );
document.write( "W=4.3166 ANSWER FOR THE WIDTH.<BR>\n" );
document.write( "L=2*4.3166-4<BR>\n" );
document.write( "L=8.6312-4<BR>\n" );
document.write( "L=4.6312 ANSWER FOR THE LENGTH.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "4.3166*4.6312=20<BR>\n" );
document.write( "20=20<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );