document.write( "Question 77571: can you please show me how to solve 2y to the second=25y+13\r
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document.write( "can you please show me how to solve 10u to the third-5u to the second=0
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Algebra.Com's Answer #55627 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! 2Y^2=25Y+13 \n" ); document.write( "2Y^2-25Y-13=0 \n" ); document.write( "(2Y+1)(Y-13)=0 \n" ); document.write( "2Y+1=0 \n" ); document.write( "2Y=-1 \n" ); document.write( "Y=-1/2 ANSWER. \n" ); document.write( "---------------------------------------------------------------- \n" ); document.write( "10U^3-5U^2=0 FACTORING OUT U^2 WE GET \n" ); document.write( "U^2(10U-5)=0 \n" ); document.write( "U^2=0 \n" ); document.write( "U=0 ANSWER \n" ); document.write( "10U-5=0 \n" ); document.write( "10U=5 \n" ); document.write( "U=5/10 \n" ); document.write( "U=1/2 ANSWER. \n" ); document.write( " |