document.write( "Question 77571: can you please show me how to solve 2y to the second=25y+13\r
\n" ); document.write( "\n" ); document.write( "can you please show me how to solve 10u to the third-5u to the second=0
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Algebra.Com's Answer #55627 by checkley75(3666)\"\" \"About 
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2Y^2=25Y+13
\n" ); document.write( "2Y^2-25Y-13=0
\n" ); document.write( "(2Y+1)(Y-13)=0
\n" ); document.write( "2Y+1=0
\n" ); document.write( "2Y=-1
\n" ); document.write( "Y=-1/2 ANSWER.
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\n" ); document.write( "10U^3-5U^2=0 FACTORING OUT U^2 WE GET
\n" ); document.write( "U^2(10U-5)=0
\n" ); document.write( "U^2=0
\n" ); document.write( "U=0 ANSWER
\n" ); document.write( "10U-5=0
\n" ); document.write( "10U=5
\n" ); document.write( "U=5/10
\n" ); document.write( "U=1/2 ANSWER.
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