document.write( "Question 916735: the perimeter of a rectangle is 60 meters and the area is 221 square meters. Find its dimensions \n" ); document.write( "
Algebra.Com's Answer #556247 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
the perimeter of a rectangle is 60 meters and the area is 221 square meters. Find its dimensions
\n" ); document.write( "***
\n" ); document.write( "let x=length of rectangle
\n" ); document.write( "let y=width of rectangle
\n" ); document.write( "2x+2y=perimeter
\n" ); document.write( "2x+2y=60
\n" ); document.write( "x+y=30
\n" ); document.write( "y=30-x
\n" ); document.write( "length*width=area
\n" ); document.write( "xy=221
\n" ); document.write( "x(30-x)=221
\n" ); document.write( "30x-x^2=221
\n" ); document.write( "x^2-30x+221=0
\n" ); document.write( "(x-13)(x-17)
\n" ); document.write( "x=13
\n" ); document.write( "or
\n" ); document.write( "x=17
\n" ); document.write( "dimensions:
\n" ); document.write( "length=17 m
\n" ); document.write( "width=13 m
\n" ); document.write( "
\n" );