document.write( "Question 916735: the perimeter of a rectangle is 60 meters and the area is 221 square meters. Find its dimensions \n" ); document.write( "
Algebra.Com's Answer #556247 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! the perimeter of a rectangle is 60 meters and the area is 221 square meters. Find its dimensions \n" ); document.write( "*** \n" ); document.write( "let x=length of rectangle \n" ); document.write( "let y=width of rectangle \n" ); document.write( "2x+2y=perimeter \n" ); document.write( "2x+2y=60 \n" ); document.write( "x+y=30 \n" ); document.write( "y=30-x \n" ); document.write( "length*width=area \n" ); document.write( "xy=221 \n" ); document.write( "x(30-x)=221 \n" ); document.write( "30x-x^2=221 \n" ); document.write( "x^2-30x+221=0 \n" ); document.write( "(x-13)(x-17) \n" ); document.write( "x=13 \n" ); document.write( "or \n" ); document.write( "x=17 \n" ); document.write( "dimensions: \n" ); document.write( "length=17 m \n" ); document.write( "width=13 m \n" ); document.write( " |