document.write( "Question 77459: Ok stan h. you go this..\r
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document.write( "-(6x-24+3x^2)/(5-26x+ 5x^2)
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document.write( "=(3^2+6x-24)/(5x^2-26x+5)
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document.write( "=3(x^2+2x-12)/(5x^2-25x-x+5)
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document.write( "=3(x^2+2x-12)/(5x(x-5)-(x-5))
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document.write( "=3(x^2+2x-12)/(x-5)(5x-1)\r
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document.write( "But what would the x equal to??
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document.write( "Graph the following rational functions, give any equations for vertical,horizontal, or oblique asymptotes.
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document.write( "-6x-24+3x^2
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document.write( "5-26x+ 5x^2 \r
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document.write( "1 solutions\r
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document.write( "Answer 55556 by stanbon(7053) on 2007-04-08 11:12:48 (Show Source): \r
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document.write( "-(6x-24+3x^2)/(5-26x+ 5x^2)
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document.write( "=(3^2+6x-24)/(5x^2-26x+5)
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document.write( "=3(x^2+2x-12)/(5x^2-25x-x+5)
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document.write( "=3(x^2+2x-12)/(5x(x-5)-(x-5))
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document.write( "=3(x^2+2x-12)/(x-5)(5x-1) \n" );
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Algebra.Com's Answer #55624 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! (6x-24+3x^2)/(5-26x+ 5x^2) \n" ); document.write( "=(3^2+6x-24)/(5x^2-26x+5) \n" ); document.write( "=3(x^2+2x-12)/(5x^2-25x-x+5) \n" ); document.write( "=3(x^2+2x-12)/(5x(x-5)-(x-5)) \n" ); document.write( "=3(x^2+2x-12)/(x-5)(5x-1)\r \n" ); document.write( "\n" ); document.write( "But what would the x equal to?? \n" ); document.write( "------------ \n" ); document.write( "You did not show any equal sign in your posting so \n" ); document.write( "the problem had no \"solution\". \n" ); document.write( "If you meant to past the following you could find \n" ); document.write( "a solution: \n" ); document.write( "(6x-24+3x^2)/(5-26x+ 5x^2)=0 \n" ); document.write( "then \n" ); document.write( "3(x^2+2x-12)/[(x-5)(5x-1)] would have a solution. \n" ); document.write( "The fraction can be zero only if the numerator is zero, so you get: \n" ); document.write( "3(x^2+2x-12)=0 \n" ); document.write( "x^*2+2x-12=0 \n" ); document.write( "x=[-2+-sqrt(4-4*12]/2 \n" ); document.write( "x=[-2+-sqrt52]/2 \n" ); document.write( "x=[-2+-2sqrt13]/2 \n" ); document.write( "x=(-1+sqrt13) or x=(-1-sqrt13) \n" ); document.write( "========= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |