document.write( "Question 77544: For a fixed rate, a fixed principal amount, and a fixed compounding cycle, the return is an exponential function of time. Using the formula, , let r = 8%, P = 1, and n = 1 and give the coordinates (t,A) for the points where t = 0, 1, 2, 3, 4. Round your answer to the hundredth's place.
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document.write( "a) Show coordinates in this space. \r
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document.write( "b) Show graph here.\r
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Algebra.Com's Answer #55623 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! For a fixed rate, a fixed principal amount, and a fixed compounding cycle, the return is an exponential function of time. Using the formula, , let r = 8%, P = 1, and n = 1 and give the coordinates (t,A) for the points where t = 0, 1, 2, 3, 4. Round your answer to the hundredth's place. \n" ); document.write( "----- \n" ); document.write( "Amt = P=(1+r/n)^(nt) \n" ); document.write( "A = 1(1+0.08/1)^(1*t) \n" ); document.write( "A = (1.08)^t \n" ); document.write( " \n" ); document.write( "a) Show coordinates in this space. \n" ); document.write( "If t=0, A= 1 \n" ); document.write( "If t=1, A=1.08 \n" ); document.write( "If t=2, A=1.08^2 \n" ); document.write( "If t=3, A= 1.08^3 \n" ); document.write( "If t=4, A= 1.08^4 \n" ); document.write( "----------------- \n" ); document.write( "b) Show graph here.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "=========== \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |