document.write( "Question 916667: I just need to make sure I'm doing these right before I spend hours doing them wrong ;-). Can someone please check my work?
\n" ); document.write( "I don't know how to make the Sigma sign, but the upper limit=8; lower limit=0; function 3*2^j
\n" ); document.write( "Here's how I did it:
\n" ); document.write( "= (3*2^0) + (3*2^1) + (3*2^2)+ (3*2^3) + (3*2^4) + (3*2^5) + (3*2^6) + (3*2^7) + (3*2^8)
\n" ); document.write( "= (3*1) + (3*2) + (3*4) + (3*8) + (3*16) + (3*32) + (3*64) + (3*128) + (3*256)
\n" ); document.write( "= 3 + 6 + 12 + 24 + 48 + 96 +192 + 384 + 768
\n" ); document.write( "= 1533
\n" ); document.write( "Is this right? And/or is there an easier way to do it? \n" ); document.write( "

Algebra.Com's Answer #556202 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"a%5B0%5D=+3\"$ , $\"a%5B1%5D=+6\"$ ,
\n" ); document.write( " $\"sum%28+a%5Bi%5D%2C+i=0%2C+8+%29+=+a%5B0%5D++%2B+6%28%281-r%5En%29%2F%281-r%29%29\"$ = 1533
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