document.write( "Question 916631: square root of 54m^3 n^3 divided by the square root of 3m n^6 = 3m root 2n over n to the second power. How do i get this answer? \n" ); document.write( "
Algebra.Com's Answer #556185 by Hawksfan(61)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "In this case use the idea that the sqr root (a)/sqr root(b) = sqr root (a/b)\r \n" ); document.write( "\n" ); document.write( "therefore sqr root [(54 m^3 n^3)/3m n^6)] = sqr root (18m^2/n^3)\r \n" ); document.write( "\n" ); document.write( "= 3m * [sqr root (2)]/n* sqr (n)\r \n" ); document.write( "\n" ); document.write( "now multiply both top and bottom by sqr root(n) because you cant have a sqr root on the bottom. \r \n" ); document.write( "\n" ); document.write( "= 3m * [sqr root (2)] * sqr root(n)/n* sqr root (n) * sqr root (n) \r \n" ); document.write( "\n" ); document.write( "= 3m sqr root(2n)/n^2 \n" ); document.write( " |