document.write( "Question 916586: I have tried solving this type of question multiple times, I am not sure if I am missing a step somewhere. The question is:\r
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document.write( "A insurance fraud inspector is going to audit 7 people from a pool of 18 people. How many different combinations are there?\r
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document.write( "I'm pretty sure you would use the formula 18!/ 7!(18-7)! however, my calculator does not have n! or any others to work these formulas so I am having to plug everything in on my own in my calculator. Have read thoroughly through my book and professor provided no lecture for this unit. In desperate need of explaining. I know that when the order doesn't matter, but you don't have the same total you would do 18*17*16....etc. Not sure what I'm doing wrong. \n" );
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Algebra.Com's Answer #556138 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! Yes, 18C7 = 18!/ 7!(18-7)! = \n" ); document.write( "... \n" ); document.write( "IF the Order, the 7 choices, are in matters...that's 18P7 \n" ); document.write( "18P7 = 18!/(18-7)! = 18!/11! = \n" ); document.write( "These concepts has nothing to do with the order You multiply \n" ); document.write( "If You can use a calculator in class/testing... You must have one with a reasonable capability. \n" ); document.write( ".... \n" ); document.write( " Time is of an essence...in homework as well as testing. \n" ); document.write( "Factorial capability (n!) is a minimum (and my guess would be any $12 calculator would have that n! button) \n" ); document.write( "albeit it pricey, the TI83 or later is very popular for statistic students, \n" ); document.write( "albeit it takes time to learn how to use it to its max. \n" ); document.write( " |