document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=916554>Question 916554</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Figuring out the graph for:\r<BR>\n" );
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document.write( "f(x) = 12x^3 - 12x^2 - 24x \r<BR>\n" );
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document.write( "I understand that I must factor: <BR>\n" );
document.write( "f(x) = 12x(x^2 - x - 2) <BR>\n" );
document.write( "f(x) = 12x(x+1)(x-2) \r<BR>\n" );
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document.write( "x-int:(0,0)(-1,0)(2,0) <BR>\n" );
document.write( "y-int:(0,0) \r<BR>\n" );
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document.write( "then I don't know what to do I have the points on the graph but don't know how I would graph this. Please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #556136 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=556136\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x) = 12x^3 - 12x^2 - 24x <BR>\n" );
document.write( " f(x) = 12x(x^2 - x - 2) <BR>\n" );
document.write( " f(x) = 12x(x+1)(x-2) <BR>\n" );
document.write( " x-int:(0,0)(-1,0)(2,0) <BR>\n" );
document.write( " y-int:(0,0) <BR>\n" );
document.write( "good Work.<BR>\n" );
document.write( "What goes Up, in this case, must go down and visa-versa<BR>\n" );
document.write( "Where does it turn: f' = 0 gives us that: at x =  -.55, 1.22  (rounded)<BR>\n" );
document.write( "f(-.55) = 7.57, f(1.22) = -25.35 (rounded)<BR>\n" );
document.write( "Regardless...for sketching using the visual of ~ -.5  and ~1 will do.<BR>\n" );
document.write( "f(-.5) = 7.5, f(1) = -24<BR>\n" );
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